捕获异常后确定异常类型?
有没有办法确定异常类型,即使你知道你用 catch all 捕获了异常?
Is there a way to determine the exception type even know you caught the exception with a catch all?
例子:
try
{
SomeBigFunction();
}
catch(...)
{
//Determine exception type here
}
推荐答案
你实际上可以在 catch(...) 中确定类型,但它不是很有用:
You can actully determine type inside a catch(...), but it is not very useful:
#include <iostream>
#include <exception>
class E1 : public std::exception {};
class E2 : public std::exception {};
int main() {
try {
throw E2();
}
catch( ... ) {
try {
throw;
}
catch( const E1 & e ) {
std::cout << "E1
";
}
catch( const E2 & e ) {
std::cout << "E2
";
}
}
}
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