如何将字符串向量内爆为字符串(优雅的方式)

2022-01-07 00:00:00 string c++ implode stl stdstring

我正在寻找将字符串向量内爆为字符串的最优雅方法.以下是我现在使用的解决方案:

I'm looking for the most elegant way to implode a vector of strings into a string. Below is the solution I'm using now:

static std::string& implode(const std::vector<std::string>& elems, char delim, std::string& s)
{
    for (std::vector<std::string>::const_iterator ii = elems.begin(); ii != elems.end(); ++ii)
    {
        s += (*ii);
        if ( ii + 1 != elems.end() ) {
            s += delim;
        }
    }

    return s;
}

static std::string implode(const std::vector<std::string>& elems, char delim)
{
    std::string s;
    return implode(elems, delim, s);
}

还有其他人吗?

推荐答案

使用 boost::algorithm::join(..):

#include <boost/algorithm/string/join.hpp>
...
std::string joinedString = boost::algorithm::join(elems, delim);

另见这个问题.

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