C++双地址运算符?(&&)
我正在阅读 STL 源代码,但我不知道 &&
地址运算符应该做什么.下面是来自 stl_vector.h
的代码示例:
I'm reading STL source code and I have no idea what &&
address operator is supposed to do. Here is a code example from stl_vector.h
:
vector&
operator=(vector&& __x) // <-- Note double ampersands here
{
// NB: DR 675.
this->clear();
this->swap(__x);
return *this;
}
地址的地址"有意义吗?为什么它有两个地址运算符而不是一个?
Does "Address of Address" make any sense? Why does it have two address operators instead of just one?
推荐答案
这是 C++11 代码.在 C++11 中,&&
标记可用于表示右值引用".
This is C++11 code. In C++11, the &&
token can be used to mean an "rvalue reference".
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