如何在类声明之外声明模板函数
#include <iterator>
#include <map>
#include <vector>
template <class T1, class T2>
class A
{
public:
typedef typename std::vector<std::pair<T1,T2> >::iterator iterator;
std::pair<iterator, bool > foo()
{
iterator aIter;
return std::pair<std::vector<std::pair<T1,T2> >::iterator, bool >(aIter ,false);
}
};
上面的代码对我来说很好用.但我想将函数的定义移到类声明之外.我试过了.
The above code works fine for me. But I want to move the definition of the function outside the the class declaration. I tried this.
template <class T1, class T2>
class A
{
public:
typedef typename std::vector<std::pair<T1,T2> >::iterator iterator;
std::pair<iterator, bool > foo();
};
template <class T1, class T2>
std::pair<std::vector<std::pair<T1,T2> >::iterator, bool > A<T1, T2>::foo()
{
iterator aIter;
return std::pair<std::vector<std::pair<T1,T2> >::iterator, bool >(aIter ,false);
}
但它没有编译.知道如何做到这一点吗?
But it is not compiling. Any Idea how to do this?
推荐答案
您再次缺少返回值中的类型名称.函数应该是:
You are again missing the typename in the return value. The function should be:
template <class T1, class T2>
std::pair<typename std::vector<std::pair<T1,T2> >::iterator, bool > A<T1, T2>::foo()
{
iterator aIter;
return std::pair<std::vector<std::pair<T1,T2> >::iterator, bool >(aIter ,false);
}
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