必须调用非静态成员函数的引用

2022-01-05 00:00:00 reference pointers c++

我使用的是 C++(不是 C++11).我需要创建一个指向类中函数的指针.我尝试执行以下操作:

I'm using C++ (not C++11). I need to make a pointer to a function inside a class. I try to do following:

void MyClass::buttonClickedEvent( int buttonId ) {
    // I need to have an access to all members of MyClass's class
}

void MyClass::setEvent() {

    void ( *func ) ( int ); 
    func = buttonClickedEvent; // <-- Reference to non static member function must be called

}

setEvent();

但是有一个错误:必须调用对非静态成员函数的引用".我应该怎么做才能指向 MyClass 的成员?

But there's an error: "Reference to non static member function must be called". What should I do to make a pointer to a member of MyClass?

推荐答案

问题在于 buttonClickedEvent 是一个成员函数，你需要一个指向 member 的指针才能调用它.

The problem is that buttonClickedEvent is a member function and you need a pointer to member in order to invoke it.

试试这个:

void (MyClass::*func)(int);
func = &MyClass::buttonClickedEvent;

然后当你调用它时，你需要一个 MyClass 类型的对象来这样做，例如 this:

And then when you invoke it, you need an object of type MyClass to do so, for example this:

(this->*func)(<argument>);

http://www.codeguru.com/cpp/cpp/article.php/c17401/C-Tutorial-PointertoMember-Function.htm

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