对重载函数的模糊调用 - int 和 int&

2022-01-05 00:00:00 reference overloading c++ 
void g(int& a)
{
    std::cout<<"int&
";
} 

void g(int a)
{
    std::cout<<"int
";
}  

int main()
{    
    int a = 2;   
    g(a); //won't compile (at least under MSVC 2012)

    std::cin.ignore();
}

这里有没有办法避免模棱两可的调用错误?类似于 g( static_cast(a) );

Is there a way to avoid ambiguous call error here ? something like g( static_cast<int&>(a) );

推荐答案

如果你可以投射，当然有一种方法来消除这个调用的歧义:

If you can cast, there is, of course a way to disambiguate the call:

g(const_cast<int const&>(a));

如果你坚持调用参考版本，解决方法就有点棘手了:

If you insist to call the reference version, the resolution is a bit more tricky:

static_cast<void(*)(int&)>(g)(a);

相关文章