我说 const_cast 然后修改绑定到临时对象的 ref-to-const 是对的吗?

My response was that I'd asked a similar question previously, where the consensus seemed to be that temporaries themselves are not inherently const, and thus that you can cast off the const-ness of a reference you have to them, and modify them through the result. And, as long as that original ref-to-const still exists, this won't affect the temporary's lifetime.

即:

int main()
{
   const int& x = int(3);

   int& y = const_cast<int&>(x);
   y = 4;

   cout << x;
}
// Output: 4
// ^ Legal and safe

我说得对吗?

^{(当然，这样的代码是否可行完全是另一回事！)}

推荐答案

没有

首先，据我所知，它是否是文字是无关.非类类型的右值总是有非 cv 限定类型(第 3.10/9 节)，但是，在第 8.5.3 节(引用的初始化)中，我们有:

int const& x = ...;