C++:const 引用，类型说明符之前与之后
中的参数有什么区别:
int foo1(const Fred &arg) {
...
}
和
int foo2(Fred const &arg) {
...
}
?我在 Parashift 常见问题解答中没有看到这种情况.
? I don't see this case covered in the parashift FAQ.
推荐答案
没有区别，因为相对于 & 从右到左读取 const，因此两者都表示对不可变 Fred 实例的引用.
No difference as const is read right-to-left with respect to the &, so both represent a reference to an immutable Fred instance.
Fred&const 表示引用本身是不可变的，即冗余;在处理 const 指针时，Fred const* 和 Fred* const 有效但不同.
Fred& const would mean the reference itself is immutable, which is redundant; when dealing with const pointers both Fred const* and Fred* const are valid but different.
这是风格问题，但我更喜欢使用 const 作为后缀，因为它可以一致地应用，包括 const 成员函数.
It's a matter of style, but I prefer using const as a suffix since it can be applied consistently including const member functions.
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