其中&符号“&"通过引用传递参数时可以放置吗?

2022-01-05 00:00:00 reference pointers c++ declaration

在我看到的例子中，参数是通过以下方式通过引用传递的:

In the examples that I saw the arguments were passed by reference in the following way:

void AddOne(int &y)

在我拥有的代码中，我看到以下语法:

In the code that I have I see the following syntax:

void AddOne(int& y)

我想知道它是否相同，或者第二种情况与第一种情况有什么不同.

I wonder if it is the same or the second case is somehow different from the first one.

推荐答案

两者完全相同.完全没有区别.

Both are exactly the same. No difference at all.

重要的是& 应该在type 和变量 名称之间.空格无所谓.

All that matters is that & should be between the type and the variable name. Spaces don't matter.

所以

void AddOne(int&  y);
void AddOne(int  &y);
void AddOne(int & y)
void AddOne(int   &     y);
void AddOne(int&y);

都一样！

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