为什么我不能使用统一初始化初始化初始化列表中的引用?

2022-01-05 00:00:00 reference c++ c++11 initializer-list uniform-initialization

也就是说，为什么会这样:

That is, why does this:

struct S {};

struct T
{
    T(S& s) : s{s} {}

    S& s;
};

int main()
{
    S s;
    T t{s};
}

给我一??个 GCC 4.7 的编译器错误:

give me a compiler error with GCC 4.7:

test.cpp: In constructor 'T::T(S&)':
test.cpp:5:18: error: invalid initialization of non-const reference of type 'S&' from an rvalue of type '<brace-enclosed initializer list>'

?

要修复错误，我必须将 s{s} 更改为 s(s).这不会破坏，呃，统一初始化的统一性吗?

To fix the error, I have to change the s{s} to s(s). Doesn't this break the, erm, uniformity of uniform initialization?

编辑:我尝试使用 clang，并且 clang 接受了它，所以也许这是一个 GCC 错误?

EDIT: I tried with clang, and clang accepts it, so perhaps it's a GCC bug?

推荐答案

是的，它是一个 错误.这是新事物，并在 2012 年 2 月的工作文件中投票(link).

Yes, its a bug. This is something new and was voted in the working paper in February 2012 (link).

Nicol Bolas 说得很好，因为 gcc 实际上是符合 FDIS 批准的 C++11 标准的编译器，因为在此之后对工作文件进行了更改.

Nicol Bolas makes a good point in that gcc is actually the conforming compiler according to the FDIS approved C++11 standard because the changes to the working paper were made after that.

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