在没有文件的情况下编译 C++ 代码
我正在尝试使用您的标准 g++ 编译器编译一些 C++ 代码.但是，不是从文件编译:
I'm trying to compile some C++ code using your standard g++ compiler. However, rather than compiling from a file:
main.cpp:
#include <iostream>
int main(){
std::cout << "Hello World!
";
return 0;
}
我更喜欢做类似的事情
g++ ... "#include <iostream>
int main(){ std::cout << "Hello World!
"; return 0;}"
之前来自 stackoverflow 的帖子表明
A previous post from stackoverflow showed that
echo "int main(){}" | gcc -Wall -o testbinary -xc++ -
有效，但我想知道它是如何工作的，并且更好，如果有办法做到这一点而无需管道内容.
works but I would like to know how it works and better yet, if there is a way to do this without the need to pipe the contents.
我正在生成运行时代码，我需要生成共享库并加载创建的函数.
I'm doing run-time code generation where I need to generate a shared library and load the functions created.
我以为会有一个标志告诉编译器嘿，我给你的是源代码而不是文件".
I thought there would be a flag to tell the compiler "hey, I'm giving you the source code and not the file".
再次感谢您的帮助！
推荐答案
echo "int main(){}";|gcc -Wall -o testbinary -xc++ -
echo "int main(){}" | gcc -Wall -o testbinary -xc++ -
有效，但我想知道它是如何工作的，并且更好，如果有办法做到这一点而无需管道内容.
works but I would like to know how it works and better yet, if there is a way to do this without the need to pipe the contents.
或者你可以说(例如在 shell 脚本中):
Alternatively you can say (e.g. in a shell-script):
gcc -Wall -o testbinary -xc++ - << EOF
int main(){}
EOF
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