强制 GCC 将 .cpp 文件编译为 C
我有一个外部提供的 .cpp 文件.它是 C 兼容代码和一些 C++ 的混合体.C++ 代码只是对 C 的封装,以利用 C++ 的特性.
I have an externally provided .cpp file. It is a mixture of C compatible code and a bit of C++ as well. The C++ code is just a wrapper around the C to take advantage of C++ features.
它使用 #ifdef __cplusplus
宏来保护 C++ 代码,这很棒.不幸的是,如果我尝试使用 GCC 进行编译,由于文件结尾,它会将其视为 C++.我知道 gcc
和 g++
之间的区别 - 我不想编译为 C++.
It uses #ifdef __cplusplus
macros to protect the C++ code, which is great. Unfortunately, if I try to compile using GCC, it treats it as C++ because of the file ending. I'm aware of the differences between gcc
and g++
- I don't want to compile as C++.
有什么办法可以强制 GCC 将此文件视为 C 文件?我试过使用例如--std=c99
,但这会正确地产生 C99 对 C++ 无效的错误.
Is there any way I can force GCC to treat this file as a C file? I've tried using e.g. --std=c99
, but this correctly produces the error that C99 isn't valid for C++.
将文件重命名为 .c 是可行的,但如果可能的话,我想避免这种情况,因为它是外部提供的,最好将其保留为原始副本.
Renaming the file to .c works, but I'd like to avoid this if possible because it's externally provided and it'd be nice for it to remain as a pristine copy.
推荐答案
gcc
的 -x
选项允许您指定其后的所有输入文件的语言:
The -x
option for gcc
lets you specify the language of all input files following it:
$ gcc -x c your-file-name.cpp
如果你只想对那个文件进行特殊处理,你可以使用 -x none
来关闭特殊处理:
If you only want to special-case that one file, you can use -x none
to shut off the special treatment:
$ gcc -x c your-filename.cpp -x none other-file-name.cpp
(your-filename.cpp
将编译为 C,而 other-file-name.cpp
将使用扩展名并编译为 C++)
(your-filename.cpp
will be compiled as C, while other-file-name.cpp
will use the extension and compile as C++)
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