为什么未命名的 C++ 对象会在作用域块结束之前销毁?

The following code prints one,two,three. Is that desired and true for all C++ compilers?

class Foo
{
      const char* m_name;
public:
      Foo(const char* name) : m_name(name) {}
      ~Foo() { printf("%s
", m_name); }
};

void main()
{
      Foo foo("three");
      Foo("one");   // un-named object
      printf("two
");
}

推荐答案

一个临时变量一直存在到创建它的完整表达式的结尾.你的变量以分号结尾.