如何输入 int64_t/uint64_t 常量?
我想要做的是定义一个等于 2^30 的常量(我可能会将其更改为 2^34 之类的值，因此我更喜欢为它设置一个大于 32 位的房间).
What I'm trying to do is to define a constant equal to 2^30 (I may change it to something like 2^34, so I prefer to have a room larger than 32 bits for it).
为什么下面的最小(?)示例无法编译?
Why the following minimal(?) example doesn't compile?
#include <stdint.h>
// test.cpp:4:33: error: expected primary-expression before numeric constant
// test.cpp:4:33: error: expected ')' before numeric constant
const uint64_t test = (uint64_t 1) << 30;
//const uint64_t test1 = (uint64_t(1)) << 30;// this one magically compiles! why?
int main() { return 0; }
推荐答案
(uint64_t 1) 是无效的语法.转换时，您可以使用 uint64_t(1) 或 (uint64_t) 1.注释掉的示例之所以有效，是因为它遵循正确的强制转换语法，就像这样:
(uint64_t 1) is not valid syntax. When casting, you can either use uint64_t(1) or (uint64_t) 1. The commented out example works because it follows the proper syntax for casting, as would:
const uint64_t test = ((uint64_t)1) << 30;
虽然这直接回答了问题，但请参阅 Shafik Yaghmour 的回答，了解如何正确定义积分常数具体尺寸.
While this directly answers the question, see the answer by Shafik Yaghmour on how to properly define an integral constant with specific size.
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