当两个链接的 static_cast 可以完成它的工作时，为什么我们在 C++ 中有 reinterpret_cast ?

Say I want to cast A* to char* and vice-versa, we have two choices (I mean, many of us think we've two choices, because both seems to work! Hence the confusion!):

struct A
{
    int age;
    char name[128];
};

A a;
char *buffer = static_cast<char*>(static_cast<void*>(&a)); //choice 1
char *buffer = reinterpret_cast<char*>(&a); //choice 2

两者都工作正常.

//convert back
A *pA = static_cast<A*>(static_cast<void*>(buffer)); //choice 1
A *pA = reinterpret_cast<A*>(buffer); //choice 2

即使这样也能正常工作！

template<class To, class From>
To any_cast(From v)
{
    return static_cast<To>(static_cast<void*>(v));
}

char *buffer = any_cast<char*>(&a); //choice 1
char *buffer = reinterpret_cast<char*>(&a); //choice 2

//convert back
A *pA = any_cast<A*>(buffer); //choice 1
A *pA = reinterpret_cast<A*>(buffer); //choice 2