转换指针类型的正确方法
考虑到以下代码(和VirtualAlloc() 返回一个 void*):
Considering the following code (and the fact that VirtualAlloc() returns a void*):
BYTE* pbNext = reinterpret_cast<BYTE*>(
VirtualAlloc(NULL, cbAlloc, MEM_COMMIT, PAGE_READWRITE));
为什么选择 reinterpret_cast 而不是 static_cast?
why is reinterpret_cast chosen instead of static_cast?
我曾经认为 reinterpret_cast 可以用于例如将指针转换为整数类型(例如 DWORD_PTR)，但是从 void* 转换为 BYTE*，不是 static_cast 好吗?
I used to think that reinterpret_cast is OK for e.g. casting pointers to and from integer types (like e.g. DWORD_PTR), but to cast from a void* to a BYTE*, isn't static_cast OK?
在这种特殊情况下是否有任何(微妙的?)差异，或者它们只是有效的指针转换?
Are there any (subtle?) differences in this particular case, or are they just both valid pointer casts?
C++ 标准是否对这种情况有偏好，建议一种方法而不是另一种方法?
Does the C++ standard have a preference for this case, suggesting a way instead of the other?
推荐答案
对于可转换的指向基本类型的指针，两个强制转换具有相同的含义；所以你说 static_cast 没问题是正确的.
For convertible pointers to fundamental types both casts have the same meaning; so you are correct that static_cast is okay.
在某些指针类型之间进行转换时，可能需要更改指针中保存的特定内存地址.
When converting between some pointer types, it's possible that the specific memory address held in the pointer needs to change.
这就是两个演员表不同的地方.static_cast 会做适当的调整.reinterpret_cast 不会.
That's where the two casts differ. static_cast will make the appropriate adjustment. reinterpret_cast will not.
因此，除非您知道需要reinterpret_cast，否则在指针类型之间static_cast 是一个很好的一般规则.
For that reason, it's a good general rule to static_cast between pointer types unless you know that reinterpret_cast is desired.
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