覆盖纯虚函数的参数数量
我已经实现了以下接口:
I have implemented the following interface:
template <typename T>
class Variable
{
public:
Variable (T v) : m_value (v) {}
virtual void Callback () = 0;
private:
T m_value;
};
一个合适的派生类可以这样定义:
A proper derived class would be defined like this:
class Derived : public Variable<int>
{
public:
Derived (int v) : Variable<int> (v) {}
void Callback () {}
};
但是,我想派生 Callback
接受不同参数的类(例如:void Callback (int a, int b))
.有办法吗?
However, I would like to derive classes where Callback
accepts different parameters (eg: void Callback (int a, int b))
.
Is there a way to do it?
推荐答案
这个问题我遇到过很多次了.
This is a problem I ran in a number of times.
这是不可能的,并且有充分的理由,但有一些方法可以实现基本相同的目标.就个人而言,我现在使用:
This is impossible, and for good reasons, but there are ways to achieve essentially the same thing. Personally, I now use:
struct Base
{
virtual void execute() = 0;
virtual ~Base {}
};
class Derived: public Base
{
public:
Derived(int a, int b): mA(a), mB(b), mR(0) {}
int getResult() const { return mR; }
virtual void execute() { mR = mA + mB; }
private:
int mA, mB, mR;
};
在行动:
int main(int argc, char* argv[])
{
std::unique_ptr<Base> derived(new Derived(1,2));
derived->execute();
return 0;
} // main
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