在 Lua 中注册 C++ 函数?
我正在尝试在 Lua 中注册一个 C++ 函数.
I am trying to register a c++ function in Lua.
但收到此错误:
CScript.cpp|39|error: argument of type 'int (CScript::)(lua_State*)' does not match 'int (*)(lua_State*)'|
int CApp::SetDisplayMode(int Width, int Height, int Depth)
{
this->Screen_Width = Width;
this->Screen_Height = Height;
this->Screen_Depth = Depth;
return 0;
}
int CScript::Lua_SetDisplayMode(lua_State* L)
{
// We need at least one parameter
int n = lua_gettop(L);
if(n < 0)
{
lua_pushstring(L, "Not enough parameter.");
lua_error(L);
}
int width = lua_tointeger(L, 1);
int height = lua_tointeger(L, 2);
int depth = lua_tointeger(L, 3);
lua_pushinteger(L, App->SetDisplayMode(width, height, depth));
return 0;
}
在主要部分:
lua_register(L, "setDisplayMode", Lua_SetDisplayMode);
推荐答案
您不能直接使用基本的 Lua C API 在 Lua 中注册 C++ 非静态成员函数.
You cannot directly register a C++ non-static member function in Lua using just the basic Lua C API.
然而,任何可以轻松将 C++ 代码与 Lua 相关联的各种机制都允许您这样做.toLua++、SWIG、Luabind 等.如果你是认真的在 Lua 中使用 C++ 对象,我建议选择其中之一并使用它,而不是编写自己的版本.我个人使用 Luabind(大部分时间;SWIG 在工具箱中占有一席之地),因为它没有某种形式的代码生成.这一切完全是在 C++ 中完成的,因此没有生成 C++ 源文件的预通过步骤.
However, any of the various mechanisms that exist for easily associating C++ code with Lua will allow you to do so. toLua++, SWIG, Luabind, etc. If you're serious about using C++ objects with Lua, I suggest picking one of those and using it, rather than writing your own version. I personally use Luabind (most of the time; SWIG has its place in the toolbox), as it is the one that doesn't have some form of code generation. It's all done purely in C++, so there's no pre-pass step that generates a C++ source file.
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