如何向未命名的类添加构造函数/析构函数?

2021-12-30 00:00:00 class constructor destructor c++ declaration

有没有办法在未命名的类中声明构造函数或析构函数?考虑以下

Is there a way to declare a constructor or a destructor in an unnamed class? Consider the following 

void f()
{
    struct {
        // some implementation
    } inst1, inst2;

    // f implementation - usage of instances
}

后续问题:这些实例当然是像任何基于堆栈的对象一样构造(和销毁)的.叫什么?它是由编译器自动分配的错误名称吗?

Follow up question : The instances are ofcourse constructed (and destroyed) as any stack based object. What gets called? Is it a mangled name automatically assigned by the compiler?

推荐答案

您不能为未命名的类声明构造函数或析构函数，因为构造函数和析构函数名称需要与类名称匹配.在您的示例中，未命名的类是本地的.它没有链接，因此不会创建损坏的名称.

You can not declare a constructor or destructor for an unnamed class because the constructor and destructor names need to match the class name. In your example, the unnamed class is local. It has no linkage so neither mangled name is created.

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