为什么复制构造函数要在 C++ 中通过引用接受其参数?
为什么必须通过引用传递复制构造函数的参数?
Why must a copy constructor's parameter be passed by reference?
推荐答案
因为不是按引用，就是按值.为此，您创建一个副本，然后调用复制构造函数.但是要做到这一点，我们需要创建一个新值，因此我们调用了复制构造函数，依此类推...
Because if it's not by reference, it's by value. To do that you make a copy, and to do that you call the copy constructor. But to do that, we need to make a new value, so we call the copy constructor, and so on...
(您将有无限递归，因为要制作副本，您需要制作副本".)
(You would have infinite recursion because "to make a copy, you need to make a copy".)
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