C++，boost:这是将 tcp://adr:port/之类的字符串解析为地址字符串和一个 int 作为端口的最快方法?

we have std::string A with tcp://adr:port/ How to parse it into address std::string and one int for port?

推荐答案

void extract(std::string const& ip, std::string& address, std::string& service)
{
   boost::regex e("tcp://(.+):(\d+)/");
   boost::smatch what;
   if(boost::regex_match(ip, what, e, boost::match_extra))
   {
     boost::smatch::iterator it = what.begin();
     ++it; // skip the first entry..
     address = *it;
     ++it;
     service = *it;
   }
}

这里服务是一个字符串的原因是你需要它作为解析器的字符串！;)