整数对哈希函数的错误
我有以下带有 unordered_map
成员的类,以及为 pair
I have the following class with an unordered_map
member, and a hash function defined for pair<int,int>
class abc
{public :
unordered_map < pair<int,int> , int > rules ;
unsigned nodes;
unsigned packet ;
};
namespace std {
template <>
class hash < std::pair< int,int> >{
public :
size_t operator()(const pair< int, int> &x ) const
{
size_t h = std::hash<int>()(x.first) ^ std::hash<int>()(x.second);
return h ;
}
};
}
但我收到以下错误:
error: invalid use of incomplete type ‘struct std::hash<std::pair<int, int> >
error: declaration of ‘struct std::hash<std::pair<int, int> >
error: type ‘std::__detail::_Hashtable_ebo_helper<1, std::hash<std::pair<int, int> >, true>’ is not a direct base of ‘std::__detail::_Hash_code_base<std::pair<int, int>, std::pair<const std::pair<int, int>, int>, std::__detail::_Select1st, std::hash<std::pair<int, int> >, std::__detail::_Mod_range_hashing, std::__detail::_Default_ranged_hash, true>’
推荐答案
不幸的是,这个程序有未定义的行为.C++11 §17.6.4.2.1:
Unfortunately, this program has undefined behavior. C++11 §17.6.4.2.1:
只有当声明依赖于用户定义的类型并且特化满足原始模板的标准库要求并且未被明确禁止时,程序才可以将任何标准库模板的模板特化添加到命名空间 std.
A program may add a template specialization for any standard library template to namespace std only if the declaration depends on a user-defined type and the specialization meets the standard library requirements for the original template and is not explicitly prohibited.
hash
仅取决于原始和标准库类型.通过在名称空间 std
之外定义散列类,并在映射声明中显式使用该散列,可以轻松解决此问题:
hash<pair<int,int>>
depends on primitive and standard library types only. This is easily worked around by defining your hash class outside of namespace std
, and using that hash explicitly in your map declaration:
struct pairhash {
public:
template <typename T, typename U>
std::size_t operator()(const std::pair<T, U> &x) const
{
return std::hash<T>()(x.first) ^ std::hash<U>()(x.second);
}
};
class abc {
std::unordered_map<std::pair<int,int>, int, pairhash> rules;
};
我在这里使用 xor 来组合配对成员的哈希值,因为我很懒,但要认真使用 xor 是一个相当糟糕的哈希组合函数.
I've used xor to combine the hashes of the pair members here because I'm lazy, but for serious use xor is a fairly crappy hash combining function.
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