Qt:是否可以在使用 foreach 宏进行迭代时删除 QList 元素?
我是 Qt 的新手,正在尝试学习习语.
I'm new to Qt and trying to learn the idioms.
foreach
文档 说:
Qt 在进入 foreach 循环时自动获取容器的副本.如果您在迭代时修改容器,则不会影响循环.
Qt automatically takes a copy of the container when it enters a foreach loop. If you modify the container as you are iterating, that won't affect the loop.
但它没有说明如何在使用 foreach
进行迭代时删除元素.我最好的猜测是这样的:
But it doesn't say how to remove an element while iterating with foreach
. My best guess is something like:
int idx = 0;
foreach (const Foo &foo, fooList) {
if (bad(foo)) {
fooList.removeAt(idx);
}
++idx;
}
必须将 idx
范围限定在循环之外(并且必须维护一个单独的循环计数器),这看起来很丑陋.
Seems ugly to have to scope idx
outside the loop (and to have to maintain a separate loop counter at all).
另外,我知道 是的,发生深度复制.foreach
制作了 QList
的副本,这很便宜,但是一旦我删除一个元素会发生什么――仍然是便宜还是正在进行昂贵的复制修改?
Also, I know that Yes, deep copy happens.foreach
makes a copy of the QList
, which is cheap, but what happens once I remove an element -- is that still cheap or is there an expensive copy-on-modify going on?
这似乎也不是惯用的 Qt.
EDIT : This doesn't seem like idiomatic Qt either.
for (int idx = 0; idx < fooList.size(); ) {
const Foo &foo = fooList[idx];
if (bad(foo)) {
fooList.removeAt(idx);
}
else ++idx;
}
推荐答案
你最好为此使用迭代器:
// Remove all odd numbers from a QList<int>
QMutableListIterator<int> i(list);
while (i.hasNext()) {
if (i.next() % 2 != 0)
i.remove();
}
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