C++ 中的 size_t 和 int 有什么区别?
在几个 C++ 示例中，我看到使用了 size_t 类型，而我会在其中使用简单的 int.有什么区别，为什么 size_t 应该更好?
In several C++ examples I see a use of the type size_t where I would have used a simple int. What's the difference, and why size_t should be better?
推荐答案
来自 友好的维基百科:
stdlib.h 和 stddef.h 头文件定义了一种名为 size_t 的数据类型，用于表示对象的大小.接受大小的库函数期望它们的类型为 size_t，而 sizeof 运算符的计算结果为 size_t.
The stdlib.h and stddef.h header files define a datatype called size_t which is used to represent the size of an object. Library functions that take sizes expect them to be of type size_t, and the sizeof operator evaluates to size_t.
size_t 的实际类型是平台相关的；一个常见的错误是假设 size_t 与 unsigned int 相同，这可能会导致编程错误，尤其是在 64 位架构变得更加普遍的情况下.
The actual type of size_t is platform-dependent; a common mistake is to assume size_t is the same as unsigned int, which can lead to programming errors, particularly as 64-bit architectures become more prevalent.
另外，查看 为什么 size_t 很重要
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