在 C++ 中存储类型

2021-12-25 00:00:00 types casting c++

是否可以将类型名称存储为 C++ 变量?例如,像这样:

Is it possible to store a type name as a C++ variable? For example, like this:

type my_type = int; // or string, or Foo, or any other type
void* data = ...;
my_type* a = (my_type*) data;

我知道在 99.9% 的情况下,有一种更好的方法可以做你想做的事,而不必求助于空指针,但我很好奇 C++ 是否允许这种事情.

I know that 99.9% of the time there's a better way to do what you want without resorting to casting void pointers, but I'm curious if C++ allows this sort of thing.

推荐答案

不,这在 C++ 中是不可能的.

No, this is not possible in C++.

RTTI typeid 运算符允许您在运行时获取有关类型的一些信息:您可以获取类型的名称并检查它是否等于另一个类型,仅此而已.

The RTTI typeid operator allows you to get some information about types at runtime: you can get the type's name and check whether it is equal to another type, but that's about it.

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