将流缓冲的内容复制到字符串

2021-12-24 00:00:00 string c++ boost boost-asio streambuf

显然 boost::asio::async_read 不喜欢字符串，因为 boost::asio::buffer 的唯一重载允许我创建 const_buffers，所以我坚持将所有内容读入流缓冲.
现在我想将 streambuf 的内容复制到一个字符串中，但它显然只支持写入 char* (sgetn())，使用 streambuf 创建一个 istream 并使用 getline().


Apparently boost::asio::async_read doesn't like strings, as the only overload of boost::asio::buffer allows me to create const_buffers, so I'm stuck with reading everything into a streambuf.

Now I want to copy the contents of the streambuf into a string, but it apparently only supports writing to char* (sgetn()), creating an istream with the streambuf and using getline().  
有没有其他方法可以在不过度复制的情况下使用streambufs内容创建字符串?

Is there any other way to create a string with the streambufs contents without excessive copying?
推荐答案
我最不喜欢这样的回答:你不想要 X，你想要 Y，这是如何做 Y"，但在这种情况下我我很确定我知道 tstenner 想要什么.

I mostly don't like answers that say "You don't want X, you want Y instead and here's how to do Y" but in this instance I'm pretty sure I know what tstenner wanted.
在 Boost 1.66 中，动态字符串添加了缓冲区类型，以便async_read可以直接调整大小并写入字符串缓冲区.

In Boost 1.66, the dynamic string buffer type was added so async_read can directly resize and write to a string buffer.


	
		相关文章