如何立即调用 C++ lambda?
来自我继承的类的构造函数需要传入一个非平凡的对象.类似于:
A constructor from a class I'm inheriting requires a non-trivial object to be passed in. Similar to this:
MyFoo::MyFoo() : SomeBase( complexstuff )
{
return;
}
complexstuff
与 MyFoo
关系不大,所以我不想传入.
The complexstuff
has little to do with MyFoo
, so I didn't want to have to pass it in.
我没有编写某种返回 complexstuff
的 1-off 临时函数,而是使用了 lambda.我花了几分钟才弄清楚我必须调用 lambda.所以我的代码现在看起来像这样:
Instead of writing some kind of 1-off temporary function that returns complexstuff
I used a lambda. What took me a few minutes to figure out is I have to invoke the lambda. So my code now looks like this:
MyFoo::MyFoo() : SomeBase(
[]()
{
/* blah blah do stuff with complexstuff */
return complexstuff;
} () )
{
return;
}
如果你没有抓住它,那就是微妙的.但是在 lambda 主体之后,我不得不放置 ()
来告诉编译器立即运行"lambda.在我弄清楚我做错了什么之后,这是有道理的.否则,如果没有 ()
来调用 lambda,gcc 会说类似这样的话:
If you didn't catch it, it is subtle. But after the lambda body, I had to put ()
to tell the compiler to immediately "run" the lambda. Which made sense after I figured out what I had done wrong. Otherwise, without the ()
to invoke the lambda, gcc says something similar to this:
error: no matching function for call to 'SomeBase(<lambda()>)'
但现在我在想――我做对了吗?在 C++11 或 C++14 中是否有更好的方法来告诉编译器我希望它立即调用我编写的 lambda?还是像我通常的做法那样附加一个空的 ()
?
But now that has me thinking -- did I do this correctly? Is there a better way in C++11 or C++14 to tell the compiler that I want it to immediately invoke a lambda I've written? Or is appending an empty ()
like I did the usual way to do this?
推荐答案
但现在我在想――我做对了吗?
But now that has me thinking -- did I do this correctly?
是的,你做到了.
在 C++11 或 C++14 中是否有更好的方法来告诉编译器我希望它立即调用我编写的 lambda?
Is there a better way in C++11 or C++14 to tell the compiler that I want it to immediately invoke a lambda I've written?
我不知道.一个 lambda 也只是一个函数对象,所以你需要有一个 ()
来调用它,没有办法绕过它(当然除了一些调用lambda 就像 std::invoke
).
Not that I know of. A lambda is also just a function object, so you need to have a ()
to call it, there is no way around it (except of course some function that invokes the lambda like std::invoke
).
如果您愿意,可以在捕获列表之后删除 ()
,因为您的 lambda 不带任何参数.
If you want you can drop the ()
after the capture list, because your lambda doesn't take any parameters.
还是像我通常的做法那样附加一个空的 ()
?
Or is appending an empty
()
like I did the usual way to do this?
是的,这是最短的路.如前所述,std::invoke
也可以替代,但它需要更多的输入.我会说使用 ()
直接调用是通常的做法.
Yes, it is the shortest way. As said before, std::invoke
would also work instead, but it requires more typing. I would say a direct call with ()
is the usual way it is done.
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