C++ 结构的函数
通常我们可以为 C++ 结构定义一个变量，如
Usually we can define a variable for a C++ struct, as in
struct foo {
int bar;
};
我们也可以为结构定义函数吗?我们将如何使用这些功能?
Can we also define functions for a struct? How would we use those functions?
推荐答案
是的，struct 与 class 相同，除了默认的访问级别(member-wise和继承方面).(以及 class 与模板一起使用时的额外含义)
Yes, a struct is identical to a class except for the default access level (member-wise and inheritance-wise). (and the extra meaning class carries when used with a template)
一个类支持的每一个功能都因此得到一个结构的支持.您使用的方法与在类中使用方法相同.
Every functionality supported by a class is consequently supported by a struct. You'd use methods the same as you'd use them for a class.
struct foo {
int bar;
foo() : bar(3) {} //look, a constructor
int getBar()
{
return bar;
}
};
foo f;
int y = f.getBar(); // y is 3
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