二维欧几里得矢量旋转
我有一个位于坐标 (0, 1) 的欧几里得向量 a.我想将 a 绕原点旋转 90 度(顺时针):(0, 0).
I have a euclidean vector a sitting at the coordinates (0, 1).
I want to rotate a by 90 degrees (clockwise) around the origin: (0, 0).
如果我对这应该如何工作有正确的理解，旋转后的结果 (x, y) 坐标应该是 (1, 0).如果我将它旋转 45 度(仍然是顺时针)，我会期望得到的坐标为 (0.707, 0.707).
If I have a proper understanding of how this should work, the resultant (x, y) coordinates after the rotation should be (1, 0).
If I were to rotate it by 45 degrees (still clockwise) instead, I would have expected the resultant coordinates to be (0.707, 0.707).
theta = deg2rad(angle);
cs = cos(theta);
sn = sin(theta);
x = x * cs - y * sn;
y = x * sn + y * cs;
使用上述代码，angle 值为 90.0 度，结果坐标为:(-1, 1).我他妈的很困惑.以下链接中的示例肯定代表上述相同的公式吗?
Using the above code, with an angle value of 90.0 degrees, the resultant coordinates are: (-1, 1).
And I am so damn confused.
The examples seen in the following links represent the same formula shown above surely?
我做错了什么?还是我误解了向量是如何旋转的?
What have I done wrong? Or have I misunderstood how a vector is to be rotated?
推荐答案
你应该从函数中移除变量:
you should remove the vars from the function:
x = x * cs - y * sn; // now x is something different than original vector x
y = x * sn + y * cs;
创建新坐标变为，避免在到达第二行之前计算x:
create new coordinates becomes, to avoid calculation of x before it reaches the second line:
px = x * cs - y * sn;
py = x * sn + y * cs;
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