c ++:可以矢量<Base>包含派生类型的对象?
标题几乎说明了一切.基本上，这样做是否合法:
The title pretty much says it all. Basically, is it legal to do this:
class Base {
//stuff
}
class Derived: public Base {
//more stuff
}
vector<Base> foo;
Derived bar;
foo.push_back(bar);
根据我看过的其他帖子，以下内容是可以的，但我不想在这种情况下使用指针，因为它更难使其线程安全.
Based on other posts I've seen, the following is okay, but I don't want to use pointers in this case because it's harder to make it thread safe.
vector<Base*> foo;
Derived* bar = new Derived;
foo.push_back(bar);
推荐答案
不，Derived 对象将是 sliced:所有额外的成员都将被丢弃.
No, the Derived objects will be sliced: all additional members will be discarded.
使用 std::vector.
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