C++ 按值而不是按位置擦除向量元素?
vector<int> myVector;
让我们说向量中的值是这个(按这个顺序):
and lets say the values in the vector are this (in this order):
5 9 2 8 0 7
如果我想删除包含值8"的元素，我想我会这样做:
If I wanted to erase the element that contains the value of "8", I think I would do this:
myVector.erase(myVector.begin()+4);
因为这会擦除第 4 个元素.但是有没有办法根据值8"擦除元素?喜欢:
Because that would erase the 4th element. But is there any way to erase an element based off of the value "8"? Like:
myVector.eraseElementWhoseValueIs(8);
还是我只需要遍历所有向量元素并测试它们的值?
Or do I simply just need to iterate through all the vector elements and test their values?
推荐答案
std::remove() 代替:
#include <algorithm>
...
vec.erase(std::remove(vec.begin(), vec.end(), 8), vec.end());
这种组合也称为擦除-删除习语.
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