如果我们已经有了 RVO，移动语义会提供什么优化?

As far as I understand one of the purposes of adding move semantics is to optimize code by calling special constructor for copying "temporary" objects. For example, in this answer we see that it can be used to optimize such string a = x + y stuff. Because x+y is an rvalue expression, instead of deep copying we can copy only the pointer to the string and the size of the string. But as we know, modern compilers support return value optimization, so without using move semantics our code will not call the copy constructor at all.

为了证明这一点，我写了这段代码:

#include <iostream>

struct stuff
{
        int x;
        stuff(int x_):x(x_){}
        stuff(const stuff & g):x(g.x)
        {
                std::cout<<"copy"<<std::endl;
        }
};   
stuff operator+(const stuff& lhs,const stuff& rhs)
{
        stuff g(lhs.x+rhs.x);
        return g;
}
int main()
{
        stuff a(5),b(7);
        stuff c = a+b;
}

    template<class T> 
void swap(T& a, T& b)   // "perfect swap" (almost)
{
    T tmp = move(a);    // could invalidate a
    a = move(b);        // could invalidate b
    b = move(tmp);      // could invalidate tmp
}

stuff func(const stuff& st)
{
    if(st.x>0)
    {
        stuff ret(2*st.x);
        return ret;
    }
    else
    {
        stuff ret2(-2*st.x);
        return ret2;
    }
}