如何将 std::string 传递给 glShaderSource?
我有以下代码:
glShaderSource(shader, 1, (const char **)data.c_str(), NULL);
但它使我的程序崩溃.如何将 std::string
转换为 const char **
?我也试过 (const char **)&
但它说需要 l 值",我不明白.当我使用此代码时它工作正常:
But it makes my program crash. How do I convert std::string
into const char **
?
I also tried (const char **)&
but it said "requires l-value" which I don't understand. It works fine when I use this code:
const char *data = "some code";
glShaderSource(shader, 1, &data, NULL);
但我不能直接从 std::string
让它工作.我可以为它分配一个新的 char
数组,但这不是很好的代码.
But I can't make it work directly from a std::string
. I could allocate a new char
array for it but that is not nice code.
我也尝试过 const GLchar
但显然它没有区别.
I also tried with const GLchar
but obviously it makes no difference.
推荐答案
data.c_str()
返回一个 const char*
,所以这样做:
data.c_str()
returns a const char*
, so do this:
const char *c_str = data.c_str();
glShaderSource(shader, 1, &c_str, NULL);
相关文章