C++ 中隐藏特定函数的方法

我有一个继承 struct A : public B,我想对 B 隐藏单个函数,这可能吗?

i have an inheritance struct A : public B, i want to hide individual functions from B, is this possible?

我知道在 A 声明中使用 using BMethod 可以实现相反的效果.

i know the opposite is possible using using BMethod in the A declaration.

干杯

推荐答案

using 关键字可用于改变可见性

The using keyword can be used to change visibility

struct A
{
    void method1();
};

struct B: public A
{
    void method2();

    private:
    using A::method1;
};

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