C++ 重载函数作为模板参数

2021-12-13 00:00:00 overloading templates c++

我的代码的简化版本在这里

the simplified version of my code is here

int foo(int x)
{
  return x;
}

int foo(int x, int y)
{
  return x+y;
}

template<typename unary_func>
int bar(int k, unary_func f)
{
  return f(k);
}

int main()
{
  bar(3, foo);
  return 0;
}

有没有办法告诉编译器我想传递的参数是第一个‘foo’?

Is there a way to tell the compiler what I want to pass as argument is the first `foo'?

推荐答案

你可以给出一个明确的模板参数:

You can give an explicit template argument:

bar<int(int)>(3, foo);

或将模棱两可的函数名称强制转换为可以从中推导出模板参数的类型:

or cast the ambiguous function name to a type from which the template argument can be deduced:

bar(3, static_cast<int(*)(int)>(foo));

或将其包装在另一个函数(或函数对象)中以消除歧义

or wrap it in another function (or function object) to remove the ambiguity

bar(3, [](int x){return foo(x);});

相关文章