GCC 问题:使用依赖于模板参数的基类成员
以下代码不能用 gcc 编译，但可以用 Visual Studio 编译:
The following code doesn't compile with gcc, but does with Visual Studio:
template <typename T> class A {
public:
T foo;
};
template <typename T> class B: public A <T> {
public:
void bar() { cout << foo << endl; }
};
我收到错误:
test.cpp:在成员函数‘void B::bar()’中:
test.cpp: In member function ‘void B::bar()’:
test.cpp:11: 错误:'foo' 未在此范围内声明
test.cpp:11: error: ‘foo’ was not declared in this scope
但它应该是！如果我将 bar 更改为
But it should be! If I change bar to
void bar() { cout << this->foo << endl; }
然后它确实编译，但我认为我不必这样做.GCC 在这里遵循的 C++ 官方规范中是否有某些内容，或者这只是一个怪癖?
then it does compile, but I don't think I have to do this. Is there something in the official specs of C++ that GCC is following here, or is it just a quirk?
推荐答案
这在 gcc-3.4.C++ 解析器在那个版本中变得更加严格――根据规范，但对于拥有遗留或多平台代码库的人来说仍然有点烦人.
This changed in gcc-3.4. The C++ parser got much more strict in that release -- per the spec but still kinda annoying for people with legacy or multi-platform code bases.
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