C++ 模板，链接错误
我在调用我拥有的模板类时遇到问题.我声明了一个新的类型名Array，它是一个模板；
I have a problem in calling a template class I have. I declared a new type name Array, which is a template;
在 .hpp 文件中:
In the .hpp file:
template <typename T>
class Array
{
public:
Array();
};
在 .cpp 文件中:
In the .cpp file:
template <typename T>
Array<T>::Array()
{
//Do something
}
主要内容:
Array<int> arr;
我收到链接错误:未解析到构造函数的外部符号.
I get Linkage error: unresolved external symbol to the ctor.
有什么想法吗?
推荐答案
模板函数，包括成员函数，必须完全写在头文件中.这意味着如果你有一个模板类，它的实现必须完全在一个头文件中.这是因为编译器需要访问整个模板定义(不仅仅是签名)，以便为模板的每个实例化生成代码.
Template functions, including member functions, must be written entirely in the header files. This means that if you have a template class, its implementation must be entirely in a header file. This is because the compiler needs to have access to the entire template definition (not just the signature) in order to generate code for each instantiation of the template.
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