c++模板部分特化成员函数

2021-12-13 00:00:00 templates c++ specialization

我是模板的新手，所以也许这是一件微不足道的事情，但我无法让它工作.我正在尝试获得类成员函数的部分专业化.最短的代码是:

I'm new to templates so maybe this is a trivial thing but I cannot get it to work. I'm trying to get partial specialization of a class member function. The shortest code would be:

template <typename T, int nValue> class Object{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object& Deform(){ 
        m_t*=nValue; 
        return *this;
    }
};

template <typename T>
Object<T,0>& Object<T,0>::Deform(){
    this->m_t = -1;
    return *this;
}

int main(){
    Object<int,7> nObj(1);
    nObj.Deform();
    std::cout<<nObj.Get();
}

我尝试过非成员函数，效果很好.成员函数的完全特化也能正常工作.

I tried with nonmember functions and that's worked fine. What also works fine is full specialization of a member function.

但是，每当我尝试使用部分规范时.的成员函数我得到形式的错误:

But, whenever I try with partial spec. of a member function I get error of the form: 

PartialSpecification_MemberFu.cpp(17): error: template argument
list must match the parameter list Object<T,0>& Object<T,0>::Deform().

希望得到任何帮助:-)

Would appreciate any help :-)

推荐答案

你不能部分特化一个成员函数，你必须部分特化整个类.因此你需要类似的东西:

You cannot partially specialize only a single member function, you must partially specialize the whole class. Hence you'll need something like:

template <typename T>
class Object<T, 0>
{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object& Deform()
    {
        std::cout << "Spec
";
        m_t = -1;
        return *this;
    }
};

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