简写 C++ if else 语句
所以我很好奇是否有一个简短的声明:
So I'm just curious if there is a short hand statement to this:
if(number < 0 )
bigInt.sign = 0;
else
bigInt.sign = 1;
我看到了所有这些关于 if a < 的简短陈述.b 等等.
I see all these short hand statements for if a < b and such.
我不确定如何正确执行此操作,并希望对此提供一些意见.
I'm not sure on how to do it properly and would like some input on this.
谢谢!
其实我刚在你们回答之前就想通了.
I actually just figured it out right before you guys had answered.
最短的解决方案是 bigInt.sign = (number <0) ?0 : 1
推荐答案
是:
bigInt.sign = !(number < 0);
!
运算符的计算结果始终为 true
或 false
.当转换为 int
时,它们分别变为 1
和 0
.
The !
operator always evaluates to true
or false
. When converted to int
, these become 1
and 0
respectively.
当然这相当于:
bigInt.sign = (number >= 0);
这里的括号是多余的,但为了清楚起见,我添加了它们.所有比较和关系运算符的计算结果为 true
或 false
.
Here the parentheses are redundant but I add them for clarity. All of the comparison and relational operator evaluate to true
or false
.
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