是否有更短的方法来编写复合“if"条件?
只是代替:
if ( ch == 'A' || ch == 'B' || ch == 'C' || .....
例如，做喜欢:
if ( ch == 'A', 'B', 'C', ...
是否有一种更短的方法来总结条件?
is there even a shorter way to summarize conditions?
推荐答案
strchr() 可用于查看字符是否在列表中.
strchr() can be used to see if the character is in a list.
const char* list = "ABCXZ";
if (strchr(list, ch)) {
// 'ch' is 'A', 'B', 'C', 'X', or 'Z'
}
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