带 for 循环的无符号 int 反向迭代
我希望 for 循环中的迭代器变量作为 unsigned int 反向迭代到 0，我想不出与 i > 类似的比较.-1，就像如果它是 signed int 一样.
I want the iterator variable in a for loop to reverse iterate to 0 as an unsigned int, and I cannot think of a similar comparison to i > -1, as you would do if it was a signed int.
for (unsigned int i = 10; i <= 10; --i) { ... }
但这似乎很不清楚，因为它依赖于无符号整数的数值溢出超过 10.
But this seems very unclear, as it is relying on the numerical overflow of the unsigned integer to be above 10.
也许我只是没有清醒的头脑，但有什么更好的方法可以做到这一点...
Maybe I just don't have a clear head, but whats a better way to do this...
免责声明:这只是一个简单的用例，10 的上限是微不足道的，它可以是任何东西，并且 i 必须是一个 unsigned int.
Disclaimer: this is just a simple use case, the upper limit of 10 is trivial, it could be anything, and i must be an unsigned int.
推荐答案
可以使用
for( unsigned int j = n; j-- > 0; ) { /*...*/ }
它从 n-1 向下迭代到 0.
It iterates from n-1 down to 0.
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