如何在类中创建模板函数?(C++)
我知道可以制作模板函数:
I know it's possible to make a template function:
template<typename T>
void DoSomeThing(T x){}
并且可以制作模板类:
template<typename T>
class Object
{
public:
int x;
};
但是是否可以在模板中创建一个类，然后将那个类中的函数创建为模板?即:
but is it possible to make a class not within a template, and then make a function in that class a template? Ie:
//I have no idea if this is right, this is just how I think it would look
class Object
{
public:
template<class T>
void DoX(){}
};
或者在某种程度上，类不是模板的一部分，但函数是?
or something to the extent, where the class is not part of a template, but the function is?
推荐答案
你的猜测是正确的.你唯一需要记住的是成员函数模板定义(除了声明)应该在头文件中，而不是cpp中，尽管它不是必须在类声明本身的主体中.
Your guess is the correct one. The only thing you have to remember is that the member function template definition (in addition to the declaration) should be in the header file, not the cpp, though it does not have to be in the body of the class declaration itself.
相关文章