在 Python 中将变量的每一项打印在单独的行上
问题描述
我正在尝试在 Python 中打印一个包含数字的列表，并且当它打印列表中的项目时，所有项目都打印在同一行.
I am trying to print a list in Python that contains digits and when it prints the items in the list all print on the same line.
print ("{} ".format(ports))
这是我的输出
[60, 89, 200]
我怎样才能看到这种形式的结果:
how can I see the result in this form:
60
89
200
我试过 print ("
".join(ports)) 但这不起作用.
I have tried print ("
".join(ports)) but that does not work.
解决方案
遍历列表并在新行打印每个项目:
Loop over the list and print each item on a new line:
for port in ports:
print(port)
或在加入之前将整数转换为字符串:
or convert your integers to strings before joining:
print('
'.join(map(str, ports)))
或告诉 print() 使用换行符作为分隔符，并使用 * splat 语法将列表作为单独的参数传递:
or tell print() to use newlines as separators and pass in the list as separate arguments with the * splat syntax:
print(*ports, sep='
')
演示:
>>> ports = [60, 89, 200]
>>> for port in ports:
... print(port)
...
60
89
200
>>> print('
'.join(map(str, ports)))
60
89
200
>>> print(*ports, sep='
')
60
89
200
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