在 kivy 中，如何控制 TextInput 使用的 VKeyboard 的高度

2022-01-15 00:00:00 python kivy

问题描述

我有一个屏幕我想问一个问题，所以在 kv 语言中，我有

I have a Screen where I want to ask a question, so in the kv language, I have

Screen:
        name: 'keyb'
        BoxLayout:
            orientation: 'vertical'
            Label:
                id: rnl
                size_hint_y: .1
                text: ''
            TextInput:
                id: tinput
                hint_text: '.mid'
                size_hint: (.8, .1)
                pos_hint: {'x': .1}
                multiline: False
                on_focus: root.focusCallback(args[1])
            Widget:
                size_hint_y: .7

当我想问问题时，我选择屏幕并将焦点设置到 TextInput

When I want to ask the question, I select the screen and set the focus to the TextInput

 self.tinput.text = ""
 self.screens.current = 'keyb'
 Clock.schedule_once(self.focusKbd, .1)

然后通过此代码级联:

def focusKbd(self, x):
    self.tinput.focus = True
def focusCallback(self, f):
    if not f:
        # Deal with input now
        self.screens.current = 'seq'

在这段代码的某个地方，我想

Somewhere in this code, I would like to

  1. 选择 TextInput 将要弹出的 VKeyboard 布局(在我的代码的其他部分会有所不同)
  2. 调整 VKeyboard 的高度.

我不明白文本输入中的 VKeyboard 来自哪里；有什么方法可以从 TextInput 中获取对它的引用吗?

I don't understand where the VKeyboard comes from in Text Input; is there some way I can get a reference to it from the TextInput?

这是对 https://stackoverflow 的重述.com/questions/36414654/how-can-i-change-the-size-of-kivys-vkeyboard 那里有提示，但还不足以让我继续前进！

This is a restatement of https://stackoverflow.com/questions/36414654/how-can-i-change-the-size-of-kivys-vkeyboard There is a hint there, but not enough to get me going!

***********************************************

********************* **************************

为了理解 Tshirtman 的回答，我把它放在我的主要小部件的顶部:

Trying to understand the answer from Tshirtman, I put this at the top of my main widget:

Window.set_vkeyboard_class(get_vkeyboard())

然后添加

def get_vkeyboard():
    print '>>>>>>>>>>>>>>>>>>>>>>>>>>in get_vkeyboard'
    return VKeyboard

我发现 get_vkeyboard() 被立即调用，早在我需要键盘之前.所以似乎我无法在 get_vkeyboard() 中动态控制 VKeyboard 的外观.如果我感到困惑(我无疑是！)，请纠正我.

I found that get_vkeyboard() was called immediately, long before I needed a keyboard. So it seems that I'm not going to be able to control anything about the appearance of the VKeyboard dynamically in get_vkeyboard(). Please correct me if I'm confused (which I undoubtedly am!).

还有其他方法可以动态修改 VKeyboard 的外观吗?

Is there some other way to modify the appearance of the VKeyboard dynamically?

附:Focus Behavior 中似乎有提示:

P.S. There seems to be a hint in Focus Behavior:

input_type 是一个 OptionsProperty，默认为text".可以是其中之一文本"、号码"、网址"、邮件"、日期时间"、电话"或地址".

input_type is an OptionsProperty and defaults to ‘text’. Can be one of ‘text’, ‘number’, ‘url’, ‘mail’, ‘datetime’, ‘tel’ or ‘address’.

我在 .kv 中的 TextInput 中添加了input_type: 'number'"，但没有任何影响.

I added "input_type: 'number'" to a TextInput in .kv, but it didn't have any affect.

解决方案

你可以使用 Window.set_vkeyboard_class 设置键盘类，但是没有什么能阻止你注册任何返回键盘实例的函数，所以您可以使用上下文(您的应用程序的状态)来动态决定将使用哪个类.由于在这种情况下您要自己返回一个实例，因此您可以决定它的大小、位置和其他详细信息.我在一些应用程序中使用了这种技术，以便在实例上使用 Animation 以将其平滑地放置在屏幕的特定位置.

You can set keyboard class using Window.set_vkeyboard_class, but nothing prevents you from registering any function that returns a keyboard instance there, so you could use the context (your app's state) to decide which class will be used, dynamically. Since you are returning an instance yourself in this case, you can decide of its size, pos, and other details. I used this technique in a few app to use Animation on the instance to place it in a particular spot of the screen smoothly.

伪例子:

from kivy.core.window import Window
from kivy.uix.vkeyboard import VKeyboard
from kivy.animation import Animation
from kivy.uix.screenmanager import ScreenManager, Screen

class KeyboardA(VKeyboard):
    def place(self):
        self.center_x = Window.center_x
        self.top = 0
        Animation(y=100, t='out_elastic', d=.4).start(self)

class KeyboardB(VKeyboard):
     def place(self):
        self.opacity = 0
        Animation(opacity=1).start(self)

class MyApp(App):
     def build(self):
         sm = ScreenManger()
         sm.add_widget(Screen(name='a'))
         sm.add_widget(Screen(name='b'))
         return sm

     def get_keyboard(self, **kwargs):
         if self.root.current == 'a':
             kb = KeyboardA(**kwargs)

         else:
             kb = KeyboardB(**kwargs)

         kb.place()
         return kb

Window.set_vkeyboard_class(app.get_keyboard)

未经测试，但你应该明白.

untested, but you should get the idea.

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