Python:NameError:未定义全局名称“foobar"

2022-01-14 00:00:00 python namespaces nameerror

问题描述

我写了以下课程:

class myClass(object):
    def __init__(self):
        pass

    def foo(self, arg1, arg2):
        pp = foobar(self, arg1, arg2)
        if pp:
            return 42
        else
            return -666


    def foobar(self, arg1, arg2):
        if arg1 == arg2:
            return 42
        else:
            return None

逻辑是荒谬的 - 忽略它.我试图这样做是从另一个实例方法调用一个实例方法 - 我得到一个 NameError.我最初认为这是由于 foo() 在定义之前调用了 foobar() - 但是在脚本中切换函数定义的顺序没有任何区别.

The logic is nonsensical - ignore it. What I am trying to so is to call an instance method from another instance method - and I am getting a NameError. I originally thought that this was due to foo() calling foobar() before it had been defined - but switching the order of the function definitions in the script made no difference.

有没有人知道是什么导致了这个错误，以及如何解决它?

Does anyone what's causing this error, and how to fix it?

解决方案

Python 不会自动将代码范围限定为本地类；你需要告诉它.

Python doesn't scope code to the local class automatically; you need to tell it to.

pp = self.foobar(arg1, arg2)

http://docs.python.org/tutorial/classes.html

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