Python:NameError:未定义全局名称“foobar"

2022-01-14 00:00:00 python namespaces nameerror

问题描述

我写了以下课程:

class myClass(object):
    def __init__(self):
        pass

    def foo(self, arg1, arg2):
        pp = foobar(self, arg1, arg2)
        if pp:
            return 42
        else
            return -666


    def foobar(self, arg1, arg2):
        if arg1 == arg2:
            return 42
        else:
            return None

逻辑是荒谬的 - 忽略它.我试图这样做是从另一个实例方法调用一个实例方法 - 我得到一个 NameError.我最初认为这是由于 foo() 在定义之前调用了 foobar() - 但是在脚本中切换函数定义的顺序没有任何区别.

The logic is nonsensical - ignore it. What I am trying to so is to call an instance method from another instance method - and I am getting a NameError. I originally thought that this was due to foo() calling foobar() before it had been defined - but switching the order of the function definitions in the script made no difference.

有没有人知道是什么导致了这个错误,以及如何解决它?

Does anyone what's causing this error, and how to fix it?


解决方案

Python 不会自动将代码范围限定为本地类;你需要告诉它.

Python doesn't scope code to the local class automatically; you need to tell it to.

pp = self.foobar(arg1, arg2)

http://docs.python.org/tutorial/classes.html

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