如何在 Selenium 中获得“nth-of-type"
问题描述
我正在使用 Selenium Webdriver 来检查这个特定段落的文本(此处以蓝色突出显示的那个):
I'm using Selenium Webdriver to check the text of this particular paragraph (the one highlighted in blue here):
但我如何查询"该段落?
But how do I 'query' that paragraph?
这是我正在尝试的(不工作):
This is what I'm trying (not working):
def test_intro_text(self):
"""Test that intro text is expected text"""
container = self.browser.find_element_by_id('visual-17')
hed_dek_wrapper = container.find_element_by_class_name('hed-dek-wrapper')
intro_text = hed_dek_wrapper.findElement('p:nth-of-type(2)')
self.assertIn(
'Over the past 20 years, we have seen an evolution.',
intro_text.text
)
我收到此错误:AttributeError: 'WebElement' object has no attribute 'findElement'
I'm getting this error: AttributeError: 'WebElement' object has no attribute 'findElement'
解决方案
findElement()
不是 Python.请尝试以下方法:
findElement()
is not a Python. Try below instead:
intro_text = hed_dek_wrapper.find_element_by_css_selector('p:nth-of-type(2)')
assert 'Over the past 20 years, we have seen an evolution.' in intro_text.text
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