Python:找到最小的整数

2022-01-14 00:00:00 python list integer

问题描述

我有以下代码:

l = ['-1.2', '0.0', '1']

x = 100.0
for i in l:
    if i < x:
        x = i
print x

代码应该在我的列表中找到最小值 (-1.2)，但是当我打印x"时，它发现该值仍然是 100.0我的代码哪里出错了?

The code should find the lowest value in my list (-1.2) but instead when i print 'x' it finds the value is still 100.0 Where is my code going wrong?

解决方案

要找到一个列表的最小值，你不妨使用 min:

To find the minimum value of a list, you might just as well use min:

x = min(float(s) for s in l) # min of a generator

或者，如果您希望将结果作为字符串而不是浮点数，请使用关键功能:

Or, if you want the result as a string, rather than a float, use a key function:

x = min(l, key=float)

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