gcc 找不到 cc1plus
问题描述
我正在尝试在 CentOS 6 上安装 python 包 pandas，但我遇到了 gcc 编译器问题:
I'm trying to install the python package pandas on CentOS 6 but I'm having problems with the gcc compiler:
sudo pip install pandas
...
creating build/temp.linux-x86_64-2.7/pandas/msgpack
gcc -pthread -fno-strict-aliasing -O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector --param=ssp-buffer-size=4 -m64 -mtune=generic -D_GNU_SOURCE -fPIC -fwrapv -DNDEBUG -O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector --param=ssp-buffer-size=4 -m64 -mtune=generic -D_GNU_SOURCE -fPIC -fwrapv -fPIC -D__LITTLE_ENDIAN__=1 -Ipandas/src/msgpack -Ipandas/src/klib -Ipandas/src -I/opt/rh/python27/root/usr/lib64/python2.7/site-packages/numpy/core/include -I/opt/rh/python27/root/usr/include/python2.7 -c pandas/msgpack/_packer.cpp -o build/temp.linux-x86_64-2.7/pandas/msgpack/_packer.o -Wno-unused-function
gcc: error trying to exec 'cc1plus': execvp: No such file or directory
error: command 'gcc' failed with exit status 1
----------------------------------------
Cleaning up...
...
所以看来我需要 cc1plus，通过阅读需要 gcc-g++.但是我已经有了 gcc-c++:
So it appears I need cc1plus, which by reading around requires gcc-g++. But I already have gcc-c++:
sudo yum install gcc-c++
...
Package gcc-c++-4.4.7-16.el6.x86_64 already installed and latest version
Nothing to do
关于gcc和cc1plus:
About gcc and cc1plus:
gcc --version
gcc (GCC) 4.8.2 20140120 (Red Hat 4.8.2-15)
which gcc
/opt/rh/devtoolset-2/root/usr/bin/gcc
locate cc1plus
/usr/libexec/gcc/x86_64-redhat-linux/4.4.4/cc1plus
下面是我自己的解决方案.有没有人有更好的方法来解决这个问题?
解决方案
解决我自己的问题:似乎 cc1plus 虽然存在，但对 gcc 不可见，因为它不在路径上.所以一个解决方案是将 cc1plus 链接到 PATH 上的目录:
Solution to my own question: It seems that cc1plus, although present, is not visible to gcc as it is not on path. So a solution is to link cc1plus to a directory on PATH:
sudo ln -s /usr/libexec/gcc/x86_64-redhat-linux/4.4.4/cc1plus /usr/local/bin/
现在 sudo pip install pandas 成功了.
(但是为什么包管理器首先把 cc1plus 放在那里?)
(But why the package manager put cc1plus there in the first place?)
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