Python，如何处理“ValueError:不支持的pickle协议:4"；错误?

2022-01-13 00:00:00 python pickle centos

问题描述

我是 Python 新手.我必须运行这个 TargetFinder 脚本(自定义分析").

I'm new to Python. I've to run this TargetFinder script ("Custom Analyses").

我安装了所有必需的 python 包，并将代码复制到我命名为 main.py 的脚本中，然后运行它.我收到了这个错误:

I installed all the required python packages, and copied the code into a script I named main.py, and ran it. I got this error:

[davide@laptop]$ python main.py 
Traceback (most recent call last):
  File "main.py", line 8, in <module>
    training_df = pd.read_hdf('./paper/targetfinder/K562/output-epw/training.h5', 'training').set_index(['enhancer_name', 'promoter_name'])
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 330, in read_hdf
    return store.select(key, auto_close=auto_close, **kwargs)
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 680, in select
    return it.get_result()
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 1364, in get_result
    results = self.func(self.start, self.stop, where)
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 673, in func
    columns=columns, **kwargs)
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 2786, in read
    values = self.read_array('block%d_values' % i)
  File "/usr/lib64/python2.7/site-packages/pandas/io/pytables.py", line 2327, in read_array
    data = node[:]
  File "/usr/lib64/python2.7/site-packages/tables/vlarray.py", line 677, in __getitem__
    return self.read(start, stop, step)
  File "/usr/lib64/python2.7/site-packages/tables/vlarray.py", line 817, in read
    outlistarr = [atom.fromarray(arr) for arr in listarr]
  File "/usr/lib64/python2.7/site-packages/tables/atom.py", line 1211, in fromarray
    return cPickle.loads(array.tostring())
ValueError: unsupported pickle protocol: 4

我不知道这个 pickle 协议是什么意思，我的同事也对此一无所知.

I've no idea about what this pickle protocol means, and also my colleagues know nothing about it.

我该如何解决这个问题?

我在 CentOS Linux 版本 7.2.1511(核心)操作系统上使用 Python 2.7.5

I'm using Python 2.7.5 on a CentOS Linux release 7.2.1511 (Core) operating system

解决方案

Pickle 协议基本上就是文件格式.从 文档，使用的协议越高，读取生成的 pickle 所需的 Python 版本越新. ... Pickle 协议版本 4 是在 Python 3.4 中添加的，您的 Python 版本(2.7.5) 不支持这个.

The Pickle protocol is basically the file format. From the documentation, The higher the protocol used, the more recent the version of Python needed to read the pickle produced. ... Pickle protocol version 4 was added in Python 3.4, your python version (2.7.5) does not support this.

要么升级到 Python 3.4 或更高版本(当前为 3.5)，要么在 pickle.dump() 的第三个参数中使用较低的协议 (2) 创建 pickle.

Either upgrade to Python 3.4 or later (current is 3.5) or create the pickle using a lower protocol (2) in the third parameter to pickle.dump().

相关文章