如何在 python 中覆盖类属性访问?
问题描述
如何在 python 中覆盖类属性访问?
How can I override class attribute access in python?
附:有没有办法单独保留对类属性的常规访问,但在缺少属性时调用更具体的异常?
P.S. Is there a way to leave regular access to class attributes alone but calling a more specific exception on missing attribute?
解决方案
__getattr__
属性在实例/类/父类上不存在时调用魔术方法.您可以使用它为缺少的属性引发特殊异常:
The __getattr__
magic method is called when the attribute doesn't exist on the instance / class / parent classes. You'd use it to raise a special exception for a missing attribute:
class Foo(object):
def __getattr__(self, attr):
# only called when self.attr doesn't exist
raise MyCustonException(attr)
如果要自定义访问类属性,需要在元类/类型上定义__getattr__
:
If you want to customize access to class attributes, you need to define __getattr__
on the metaclass / type:
class BooType(type):
def __getattr__(self, attr):
print attr
return attr
class Boo(object):
__metaclass__ = BooType
boo = Boo()
Boo.asd # prints asd
boo.asd # raises an AttributeError like normal
如果您想自定义 all 属性访问,请使用 __getattribute__
魔术方法.
If you want to customize all attribute access, use the __getattribute__
magic method.
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